[Proj] Have LCC center terms, need PROJ.4 terms

Andre Joost andre+joost at nurfuerspam.de
Thu Feb 13 10:53:53 EST 2014

Am 12.02.2014 22:41, schrieb Andre Joost:
> Subtract the result
> 595747.57	 104990.12
> from 828000 (that is 138x1200/2, the center of the raster grid)
> and you get
> x_0=232252. and y_0=723010.

Just to get it right:
the inversed values should go into the lower left corner values of the 
ASCII Grid header:

nrows        138
ncols        138
xllcorner    -232252.
yllcorner    -723010.
cellsize     12000
NODATA_value -32768

and with that no false Easting or Northing is necessary for the projection:

+proj=lcc +lat_1=39.338 +lat_0=39.338 +lon_0=-84 +k_0=1 +x_0=0 +y_0=0 
+a=6371229 +b=6371229 +towgs84=0,0,0,0,0,0,0 +units=m +no_defs

André Joost

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